GCSE Mathematics  ›  M5.2 Combined events and tree diagrams

Combined events and tree diagrams

Free GCSE Mathematics practice questions on Combined events and tree diagrams. Aligned with the UK Department for Education GCSE subject content — works for any UK GCSE exam board. Sample questions below with detailed mark schemes. Sign up to practise the full set with spaced repetition.

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Suggest — 2 marks

A student is investigating the reliability of a new type of light bulb. They test two bulbs independently. Each bulb has a probability of 0.8 of lasting longer than 1000 hours. The student wants to use a tree diagram to represent all possible outcomes.

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  • (a) The two branches should represent the outcomes for the first bulb (or first event) / bulb 1 lasting longer than 1000 hours OR not lasting longer than 1000 hours. Accept: 'success and failure' or 'works and doesn't work' or equivalent outcomes for the first bulb.
  • (b) 0.2 (or 1 − 0.8 or 20% or 1/5). Accept equivalent fractions or percentages.

Define — 3 marks

A quality control manager at a manufacturing plant tests electronic components for defects. She randomly selects components and tests them twice independently. Each test has a probability of correctly identifying a defective component. The manager uses a tree diagram to calculate the probability that a component will pass both tests.

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  • (a) Award 1 mark for: Events where the outcome of one event does not affect the probability of the other event occurring / the result of the first test does not influence the result of the second test.
  • (b) Award 1 mark for: A combined event is when two or more separate events occur together / the result of two or more events considered simultaneously. Award 1 mark for: Tree diagrams show all possible outcomes by branching to represent each stage/event, allowing probabilities to be multiplied along branches to find the probability of combined events.

Calculate — 2 marks

A bag contains 5 red counters and 3 blue counters. A counter is taken at random from the bag, its colour is recorded, and then it is replaced. A second counter is then taken at random from the bag.

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  • (a) 5/8 × 5/8 or equivalent method
  • (a) 25/64 or 0.390625 or 39.0625%
  • (b) 5/8 × 3/8 + 3/8 × 5/8 or equivalent method
  • (b) 30/64 = 15/32 or 0.46875 or 46.875%

Show — 3 marks

A bag contains 4 green counters and 6 yellow counters. Mia takes a counter at random from the bag, notes its colour, and replaces it. She then takes a second counter at random. The tree diagram shows the possible outcomes.

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  • (a) 4/10 oe
  • (b) Correct method: (4/10 × 6/10) + (6/10 × 4/10) oe
  • (b) Complete working shown leading to 12/25 oe (e.g., 24/100 + 24/100 = 48/100 = 12/25)

Explain — 2 marks

A fair spinner has 4 equal sections numbered 1, 2, 3 and 4. The spinner is spun twice. The tree diagram below shows all possible outcomes.

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  • (a) 1/4 or 0.25
  • (b) Because there are 4 outcomes for the first spin AND 4 outcomes for the second spin, and 4 × 4 = 16 (or equivalent)
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