GCSE Mathematics  ›  M3.2 Percentages and percentage change

Percentages and percentage change

Free GCSE Mathematics practice questions on Percentages and percentage change. Aligned with the UK Department for Education GCSE subject content — works for any UK GCSE exam board. Sample questions below with detailed mark schemes. Sign up to practise the full set with spaced repetition.

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Calculate — 3 marks

A student measures the resistance of a wire at room temperature (20°C) and finds it to be 8.5 Ω. When the wire is heated to 80°C, the resistance increases to 10.2 Ω due to increased atomic vibrations.

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  • (a) 10.2 − 8.5 = 1.7 Ω (1 mark for correct calculation and unit)
  • (b) (1.7 ÷ 8.5) × 100 = 20% (1 mark for correct percentage change calculation with or without showing working)
  • (c) 10.2 × 1.20 = 12.24 Ω OR 10.2 + (10.2 × 0.20) = 12.24 Ω (1 mark for correct final answer with unit; accept 12.2 Ω or 12.24 Ω)

Explain — 4 marks

A school is upgrading its lighting system. The old system uses 500 W of electrical power. The new LED system uses 150 W of electrical power.

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  • (a) 500 - 150 = 350 W (or equivalent correct calculation)
  • (b) Correct method: (350 ÷ 500) × 100 or equivalent fraction calculation
  • (b) Correct answer: 70% (accept 70.0%)
  • (c) Lower power consumption reduces electricity costs / energy bills / running costs for the school (or equivalent statement about financial saving)

Calculate — 2 marks

A shop is having a sale on all items. The original price of a jacket is £45.

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  • (a) £36
  • (b) £41.40

Show — 3 marks

A shop sells a tablet for £240. In a sale, the price of the tablet is reduced by 20%. After the sale, the price is increased from the sale price back to £240.

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  • (a) 20% of £240 = £48 or £240 × 0.20 seen
  • (a) £240 − £48 = £192 or £240 × 0.80 = £192
  • (b) 25% or complete method: (£240 − £192) ÷ £192 × 100

Describe — 3 marks

A clothing shop sells jackets. In January, the shop increases the price of a jacket by 20%. In February, the shop reduces the price of the same jacket by 20% of the new price.

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  • (a) Multiply by 1.20 then by 0.80 (or equivalent method)
  • (b) States that 1.20 × 0.80 = 0.96 (or 96%)
  • (b) Concludes the final price is 96% of original / 4% less than original (not the same)
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