Compare — 4 marks
A mechanic uses two different tools to loosen a stubborn bolt on a car engine. Tool A is a standard spanner with a handle length of 0.25 m. Tool B is an adjustable wrench with a handle length of 0.15 m. Both tools are applied perpendicular to the bolt at the same point, and the mechanic applies the same force of 150 N to each tool.
- (a) Calculate the moment produced by each tool when the force is applied. [2 marks]
- (b) Compare the effectiveness of the two tools for loosening the bolt. Explain your answer in terms of moments. [2 marks]
Show mark scheme
- (a) Tool A: moment = force × perpendicular distance = 150 × 0.25 = 37.5 N·m (1 mark)
- (a) Tool B: moment = force × perpendicular distance = 150 × 0.15 = 22.5 N·m (1 mark)
- (b) Tool A is more effective because it produces a larger moment (37.5 N·m compared to 22.5 N·m) (1 mark)
- (b) The longer handle length of Tool A (0.25 m) creates a greater perpendicular distance from the pivot (bolt), which increases the turning effect for the same applied force (1 mark)