Show — 3 marks
A delivery driver pushes a cardboard box across a wooden warehouse floor. The box has a mass of 25 kg and experiences a friction force of 80 N opposing its motion. The driver applies a horizontal pushing force to move the box at constant velocity.
- (a) Show that the pushing force applied by the driver is 80 N. [1 mark]
- (b) The driver then pushes with a force of 120 N. Show that the resultant force on the box is 40 N in the direction of motion. [1 mark]
- (c) Using F = ma, show that the acceleration of the box is 1.6 m/s². (You may assume the friction force remains constant.) [1 mark]
Show mark scheme
- (a) At constant velocity, acceleration is zero, so resultant force = 0 N (or pushing force equals friction force) / pushing force = 80 N
- (b) Resultant force = 120 N − 80 N = 40 N (or equivalent correct subtraction of friction from applied force)
- (c) a = F ÷ m = 40 ÷ 25 = 1.6 m/s² (or equivalent correct rearrangement and calculation)